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What is Overriding in java?

Java  Teacher
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 If a class inherits a method from its super class, then there is a chance to override the method provided that it is not marked final.

The benefit of overriding is: ability to define a behavior that's specific to the sub class type. Which means a subclass can implement a parent calss method based on its requirement.

In object oriented terms, overriding means to override the functionality of any existing method.

 Let us look at an example.

class Animal{   public void move()
{ System.out.println("Animals can move");
}}class Dog extends Animal{ public void move()
{ System.out.println("Dogs can walk and run");
}}public class TestDog{ public static void main(String args[])
{ Animal a = new Animal(); // Animal reference and object
Animal b = new Dog(); // Animal reference but Dog object
a.move();// runs the method in Animal class
b.move();//Runs the method in Dog class }}
This would produce following result:
Animals can moveDogs can walk and run
In the above example you can see that the even though b is a type of Animal it runs
the move method in the Dog class. The reason for this is : In compile time the
check is made on the reference type. However in the runtime JVM figures out the
object type and would run the method that belongs to that particular object.

Therefore in the above example, the program will compile properly since Animal class has the method move. Then at the runtime it runs the method specific for that object.

Consider the following example :

 class Animal{ public void move(){ System.out.println("Animals can move"); }}class Dog extends Animal{ public void move(){ System.out.println("Dogs can walk and run"); } public void bark(){ System.out.println("Dogs can bark"); }}public class TestDog{ public static void main(String args[]){ Animal a = new Animal(); // Animal reference and object Animal b = new Dog(); // Animal reference but Dog object a.move();// runs the method in Animal class b.move();//Runs the method in Dog class b.bark(); }}

 This would produce following result:

TestDog.java:30: cannot find symbolsymbol  : method bark()location: class Animal               
b.bark(); ^

This program will throw a compile time error since b's reference type Animal doesn't have a method by the name of bark.

 


 

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Reader's comments(2)
1: Good
Posted by:AK - 12 Oct, 2017
2: Hai
Posted by:zxc - 12 Oct, 2017