PHP CODE for date.........

<?php

$datein = '1998-09-21';
if(preg_match('/[0-9]{4}-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])/', $datein,$parts)){
print_r( $parts);
print_r($parts[2]."/" .$parts[1]."/" .$parts[0]);
}


?>

where i am mistaken in this code, as i am getting month and day well but for years, it show me full date........ please correct me or advice me to do in right manner.

Please use code below and it will give output as you need

<?php

$datein = '1998-09-21';
if(preg_match('/([0-9]{4})-(0[1-9]|1[0-2])-(0[1-9]|[1-2][0-9]|3[0-1])/', $datein,$parts)){
print_r( $parts);
echo "<br />";
print_r($parts[3]."/" .$parts[2]."/" .$parts[1]);
// print_r($parts[1]);
}

?>